((6x-5)^2+8)/3^2=0

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Solution for ((6x-5)^2+8)/3^2=0 equation: 


x in (-oo:+oo)

((6*x-5)^2+8)/(3^2) = 0

((6*x-5)^2+8)/9 = 0

(6*x-5)^2+8 = 0

(6*x-5)^2+8 = 0

36*x^2-60*x+33 = 0

36*x^2-60*x+33 = 0

3*(12*x^2-20*x+11) = 0

12*x^2-20*x+11 = 0

DELTA = (-20)^2-(4*11*12)

DELTA = -128

DELTA < 0

3 = 0

3 = 0

3/9 = 0

x belongs to the empty set

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